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One alloy of metal contains 90% copper and 10% tin. Another contains 93% copper and 4% tin. If they are mixed so that the mixture may contain 9% of tin, what percent of copper will it contains?

A.	90.5%	B.	81.33%
C.	77%	D.	98%

Answer and Explanation

Answer:90.5%

Explanation:
Quantity of Tin Alloy1=10 and Alloy2=4
Quantity of Mixture 9
Proportion 5:1
The two alloys should be mixed in the ratio 5:1
Amount of copper in the mixture = 5(90/100)+1(93/100) = 5.43
% of copper in the mixture = [5.43/(5+1)]100= 90.5%

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