Permutation and Combination - Discussion Page For Q.251 | Aptitude Questions and Answers | Aptitude Free Online-Tests | LucentBlackBoard

Home > Arithmetic Aptitude > Permutation and Combination > Questions and Answers Discussion

In how many different ways can the letters of the word 'DETAIL' be arranged in such a way that the vowels occupy only the odd positions?

A.	32	B.	48
C.	36	D.	60
E.	120

Answer and Explanation

Answer:36

Explanation:
There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.
Let us mark these positions as under:
(1) (2) (3) (4) (5) (6)
Now, 3 vowels can be placed at any of the three places out 4, marked 1, 3, 5.
Number of ways of arranging the vowels = 3P3 = 3! = 6.
Also, the 3 consonants can be arranged at the remaining 3 positions.
Number of ways of these arrangements = 3P3 = 3! = 6.
Total number of ways = (6 x 6) = 36.

Comment on this Question
Name:

LucentBlackBoard.com has the web's largest collection of over 15,000 aptitude questions and answers with detailed explanation which include subjects like Arithmetic Aptitude, Logical Reasoning, Verbal Ability, General Knowledge, Programming Skills and more!

Our online education portal provides a unique and standard learning experience for students. We enable the students to prepare for most of the entrance and competitive exams like MBA (MAT, GMAT), Engineering (IIT-JEE, AIEEE, GATE), Employment (IAS, Bank PO, Railway, UGCNET), Civil Services and many more. We bring you the best in education by providing technical excellence and creating innovative solutions. We provide facility for online test preparation that offers 24/7 access to relevant subject matter and relative tests. These test preparations help the students to groom themselves and get prepared before actually facing the examination.