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A coin is tossed 10 times. Find the probability of obtaining head at least once.

A.	1/210	B.	10/210
C.	9/210	D.	210 – 1 / 210

Answer and Explanation

Answer:210 – 1 / 210

Explanation:
Let E be the event of heads occurring at least once and E- be the event of heads not occurring at all i.e. all tails.
=> P(E) = 1 – P(E dash)
=> 1 – ½10 = 210 – 1 / 210

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