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Q: A car pursues a rat and takes 4 leaps for every 5 leaps of the rat; but in terms of distance 3 leaps of the car are equal to 4 leaps of the rat. Compare the distance traveled by the cat and the rat in a specified time.
A. 3:5  B. 16:15
C. 15:16 D. 5:3

Answer and Explanation

Answer:16:15

Explanation:
Let 3 leaps of cat = 4 leaps of rat = k
One leap of cat = k/3 and one leap of rat = k/4
Cat takes 4 leaps for every 5 leaps of rat.
Distance traveled by cat / distance traveled by rat
4 ×k/3 / 5 × k/4
4/3 ÷ 5/4 = 16 / 15

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