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Mayur left for his school at 6 am by foot and walked at the rate of 2 kmph. After reaching his school he found it was closed and immediately turned back and started walking back to his home at 3 kmph. If he reached his home at 9 am, find the distance between his school and his home.

A.	2.5 km	B.	7.2 km
C.	7 km	D.	3.6 km

Answer and Explanation

Answer:3.6 km

Explanation:
Average speed of Mayur = (2*2*3)/(2 + 3) = 2.4 km/hr
If d is he distance between the school and Mayur’s home, then total distance walked by Mayur = 2d, and the total time taken is 3 hours
2.4 = 2d/3
7.2 = 2d
d = 3.6 km

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