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Three towns X, Y, and Z are on a river which flows uniformly. Y is equidistant from X and Z. If a boats man rows from X to Y and back in 10 hours and X to Z in 4 hours, find the ratio of speed of the boats man in still water to the speed of the current.

A.	2:5	B.	5:3
C.	3:5	D.	1:2

Answer and Explanation

Answer:5:3

Explanation:
X ------------ Y ------------ Z
If â€˜dâ€™ is the distance between X and Y, then â€˜dâ€™ is the distance between Y and Z.
Now the total time for the batsman to row from X to Z is 4 hours. Therefore, time to row from X to Y is 2 hours.
Also the time for the boats man to row from X to Y and back is 10 hours. Hence, time required to row from Y to X is 8 hours.
If, a: speed of boats man in still water
b: speed of the river
d/(a + b) = 2; d/(a â€“ b) = 8
2*(a + b) = 8*(a â€“ b)
a + b = 4a â€“ 4b
3a = 5b
a:b = 5:3

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