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Q: Betty started from her home to school 15 minutes before her normal time. She slowed her driving speed by 20% and reached her school at normal time. What is the time taken for her to travel between her home and the school today?
A. 75 min B. 60 min 
C. 70 min D. None of these

Answer and Explanation

Answer:75 min

Explanation:
On any normal day, Betty has a fixed speed , ‘s’ and fixed amount of time ‘t’ to reach her school. So the distance ‘d’ is,
D = S × T
In the given situation, betty travelled an extra 15 minutes, but at a reduced speed. So Betty covered the distance, ‘d’ at speed
S × 80/100 and in t + 15 minutes
d( s × 80/100) (t + 15)
As the distance in both the cases is the same, we can say that ,
S × t = ( s × 80/100) (t + 15)
Hence, t = 4/5t + 12
1/5t = 12 or t = 60 minutes
Hence, today she has taken t + 15 = 75 minutes

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