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Two taps A and B can separately fill a cistern in 10 and 12 min respectively. If the emptying tap C is open, then the two filling taps can together fill the cistern in 15 minutes. When the cistern is full, how long will it take for the tap C alone to empty the cistern?

A.	8×4/7 min	B.	7 × ½ min
C.	10 min	D.	12 min

Answer and Explanation

Answer:8×4/7 min

Explanation:
Let the tap alone C take x minutes to empty the cistern, then
1/x = 1/10 + 1/12 – 1/15 = 6 + 5 – 4/ 60 = 7/60
x = 60/7 min, i.e. 8 × 4/7 min

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