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What is the output of this program?
struct point
{
int x;
int y;
};
struct point origin,*pp;
main()
{
pp=&origin;
printf("origin is(%d%d)\n",(*pp).x,(*pp).y);
printf("origin is (%d%d)\n",pp->x,pp->y);
}

A.	origin is(0,0) origin is(0,1)	B.	origin is(1,1) origin is(0,0)
C.	origin is(0,0) origin is(0,0)	D.	None of these

Answer and Explanation

Answer:origin is(0,0) origin is(0,0)

Explanation:
pp is a pointer to structure. we can access the elements of the structure either with arrow mark or with indirection operator.
Note:
Since structure pointer is globally declared x & y are initialized as zeroes

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