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What is the output of following C code?

#define clrscr() 100
main()
{
clrscr();
printf("%d\n",clrscr());
}

A.	100	B.	200
C.	Compiler Error	D.	null

Answer and Explanation

Answer:100

Explanation:
Preprocessor executes as a separate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs. The input program to compiler looks like this :
main()
{
100;
printf("%d\n",100);
}
Note:
100; is an executable statement but with no action. So it doesn't give any problem

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