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What will be the output of following C code?
#define square(x) x*x
main()
{
int i;
i = 64/square(4);
printf("%d",i);
}

A.	16	B.	64
C.	42	D.	4

Answer and Explanation

Answer:64

Explanation:
the macro call square(4) will substituted by 4*4 so the expression becomes i = 64/4*4 . Since / and * has equal priority the expression will be evaluated as (64/4)*4 i.e. 16*4 = 64

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