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1. What will be the output of the program?
public class RTExcept {
public static void throwit (){
System.out.print("throwit ");
throw new RuntimeException();
}
public static void main(String [] args){
try{
System.out.print("hello ");
throwit();
}catch (Exception re ) {
System.out.print("caught ");
}finally{
System.out.print("finally ");
}
System.out.println("after ");
}
}

A.	hello throwit caught	B.	Compilation fails
C.	hello throwit RuntimeException caught after	D.	hello throwit caught finally after

Answer and Explanation

Answer:hello throwit caught finally after

Explanation:
The main ( ) method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal.
A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.

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