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class A{
public static void main(String[] args) {
try {
args = null;
args[0] = "test";
System.out.println(args[0]);
} catch (Exception ex) {
System.out.println("Exception");
} catch (NullPointerException npe) {
System.out.println("NullPointerException");
}
}
What is the result?

A.	test	B.	Exception
C.	Compilation fails.	D.	NullPointerException

Answer and Explanation

Answer:Compilation fails.

Explanation:
Whenever you write number of catch blocks, catch block with super class (Exception)should be always at the end. Because if you write first then rest of the catch blocks will not going to execute. If you write super class Exception first then rest of the exception type next then it will throw compile time error. So in our program NullPointerException should come first then Exception class.

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