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class A{
void display() throws IOException,FileNotFoundException {
System.out.println(“class A”); }
}
class B extends A {
void display() throws IOException, FileNotFoundException,NullPointerException {
System.out.println(“class B”); }
}
class Test {
Public static void main(String args[]){
B b=new B();
b.display(); }
}
Output?

A.	class A	B.	class B
C.	class A, class B	D.	compile time error

Answer and Explanation

Answer:compile time error

Explanation:
In the above program class A is super class and it is throwing two exceptions. In class B which is child class of A must throw less number of exceptions compare to A. If child class throws more number of exceptions compare to super then the program will not compile successfully.
So d) is correct.

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