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class A{
void display() throws IOException,FileNotFoundException {
System.out.println(“class A”); }
}
class B extends A {
void display() throws ClassNotFoundException, SQLException {
System.out.println(“class B”); }
}
class Test {
Public static void main(String args[]){
B b=new B();
b.display();

}
}
Output?

A.	class A	B.	class B
C.	class A, class B	D.	compile time error

Answer and Explanation

Answer:compile time error

Explanation:
In the above program class A is super class and it is throwing two exceptions, in class B which is child class of A must throw less number of exceptions compare to A and child class B must throw same type of exceptions as class A , if the child class throws other type of exceptions compare to super then the program will not compile successfully.
So d) is correct.

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