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What will be the output of the program?

String x = "xyz";
x.toUpperCase(); /* Line 2 */
String y = x.replace('Y', 'y');
y = y + "abc";
System.out.println(y);

A.	abcXyZ	B.	abcxyz
C.	xyzabc	D.	XyZabc

Answer and Explanation

Answer:xyzabc

Explanation:
Line 2 creates a new String object with the value "XYZ", but this new object is immediately lost because there is no reference to it. Line 3 creates a new Stringobject referenced by y. This new String object has the value "xyz" because there was no "Y" in the String object referred to by x. Line 4 creates a new Stringobject, appends "abc" to the value "xyz", and refers y to the result.

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