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class A{

Static{
String all[]=new String[0];
Main(null);
}
Public static void main(String args[]){
System.out.println(â€œmainâ€);}
}

A.	compile time error	B.	runtime error
C.	main main	D.	exception

Answer and Explanation

Answer:main main

Explanation:
here we have declared SIB(static initialization block), JVM always executes SIB first before the main() method , then it executes main() method,they have declared string array with size 0, in 0th position null will be stored. here from SIB they are calling main() method by passing null as parameter so because of calling main() in SIB it displays â€œmainâ€ , then JVM executes main() method so again â€œmainâ€ will be displayed . so ans c) is correct.

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