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What is the output for the below code ?

class A implements Runnable{
public void run(){
try{
for(int i=0;i<4;i++){
Thread.sleep(100);
System.out.println(Thread.currentThread().getName());
}
}catch(InterruptedException e){
}
}
}
public class Test {
public static void main(String argv[]) throws Exception{
A a = new A();
Thread t = new Thread(a,"A");
Thread t1 = new Thread(a,"B");
t.start();
t.join();
t1.start();
}
}

A.	A A A A B B B B	B.	A B A B A B A B
C.	Output order is not guaranteed	D.	Compilation succeed but Runtime Exception

Answer and Explanation

Answer:A A A A B B B B

Explanation:
t.join(); means Threat t must finish before Thread t1 start.

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