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What happens when the following code is compiled and run.

Select the one correct answer.
for(int i = 2; i < 4; i++)
for(int j = 2; j < 4; j++)
assert i!=j : i;

A.	The class compiles and runs, but does not print anything.	B.	The number 2 gets printed with AssertionError
C.	compile error	D.	The number 3 gets printed with AssertionError

Answer and Explanation

Answer:The number 2 gets printed with AssertionError

Explanation:
When i and j are both 2, assert condition is false, and AssertionError gets generated. .

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