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What is the output for the below code ?

1. public class Test {
2. public static void main(String[] args){
3. byte i = 128;
4. System.out.println(i);
5. }
6. }

A.	128	B.	0
C.	Compilation fails with an error at line 3	D.	Compilation fails with an error at line 4

Answer and Explanation

Answer:Compilation fails with an error at line 3

Explanation:
byte can only hold up to 127. So compiler complain about possible loss of precision.

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