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public class Identifier {
public static void main(String[] args) {
double strictfp=5.02;
strictfp+=.333;
System.out.print(strictfp);
}
}

A.	5.353	B.	5.353D
C.	5.353d	D.	Compiler error

Answer and Explanation

Answer:Compiler error

Explanation:
In java programming language variable name includes alphabet, digits few special characters like underscore (_), dollar singe ($) but it should not be any reserved word of java language. Here strictfp is keyword of java cannot be name of variable

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