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Time left :





Note:

1. Total number of questions : 15.

2. Time alloted : 20 minutes.

3. Each question carry 1 mark, no negative marks.

4. Click the 'Submit Test' button given in the bottom of this page to Submit your answers.

5. Test will be submitted automatically if the time expired.

6. Don't refresh the page.

Result and Statistics

Time Left :

Result and Statistics ( Test No : online_test_number )

A. Number Of Question

15

B. Number Of Attempted

-

C. Number Of Correct Answer

-

D. Number Of Wrong Answer ( D = B-C )

-

E. Total Score ( E = C )

-

F. Accuracy Rate ( F = C / B * 100 )

-

G. Total Percentage ( G = C / A * 100 )

-



Note:

1.

Which of the following companies had the highest percentage increase in sales from 2001 to 2004?

A.    P Wrong Right

B.    Q Wrong Right

C.    R Wrong Right

D.    S Wrong Right

E.    Cannot be determined Wrong Right

Answer : Q

Explanation : P = 1.25 x 1.4 x 1.1 = 1.925 = 92.5%
=> Q = 1.50 x 1.20 x 1.25 = 2.25 = 125%
=> R = 1.20 x 1.25 x 1.40 = 2.10 = 110%
=> S = 1.20 x 1.10 x 1.30 = 1.716 = 71.6%
=> The highest increase was for company Q.

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2.

If the sales of company R in 2001 was Rs. 120 crores, then what was its sales (in Rs. crores) in 2003?

A.    160 Wrong Right

B.    172  Wrong Right

C.    180 Wrong Right

D.    192 Wrong Right

E.    205 Wrong Right

Answer : 180

Explanation : The sales of company R in 2003 was
=> 120 x 1.2 x 1.25 = 180 crores.

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3.

If the ratio of the sales of P and S in the year 2000 was 2:1, then what was the ratio of their sales in 2004?

A.    40:27 Wrong Right

B.    42:25 Wrong Right

C.    39:21 Wrong Right

D.    28:13 Wrong Right

E.    None of these Wrong Right

Answer : 28:13

Explanation : Let the sales of P and S in 2000 be 200 and 100 respectively. Increase in sales of P from 2000 to 2004 = 200 x 1.2 x 1.25 x 1.4 x 1.1
=> Increase in sales of S from 2000 to 2004
=> = 200 x 1.25 x 1.2 x 1.1 x 1.3
=> Required ratio = 2000 x 1.4 / 100 x 1.3 = 28/13

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4.

If the expenses of company R in the year 2001 was 60% of its sales and the expenses increased by 100% form 2001 to 2004, then its profits in 2004, when compared to that in 2001 was.

A.    Higher Wrong Right

B.    Lower Wrong Right

"/> C.    Equal Wrong Right

D.    Either 1 or 3 Wrong Right

E.    Cannot be determined Wrong Right

Answer : Higher

Explanation : As the expenses of company R in 2001 was 60% of its sales and it increased by 100% from 2001 to 2004, while the sales increased by 110% in the same period, we can conclude that the profits would have increased from 2001 to 2004

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5.

If the ratio of sales of companies Q and R in 2000 was 1: 2, then by what percentage should the sales of company Q grow in 2005, when compared to that in 2004, for the sales of company Q in 2005 to be equal to that of company R in 2004

A.    62 Wrong Right

B.    70 Wrong Right

C.     78 Wrong Right

D.    85 Wrong Right

E.    95 Wrong Right

Answer :  78

Explanation : increase in sales of Q from 2000 to 2004 = 1.1 x 1.5 x 1.2 x 1.25 = 2.475
=> 147.5%
=> Increase in sales of R from 2000 to 2004
=> = 1.05 x 1.2 x 1.25 x 1.4 = 2.205 = 120. 5%
=> Had the sales of Q and R in 2000 been 100 and 200 respectively, their sales in 2004 would hav been respectively 247.5 and 441.
=> Sales of company Q has to increase by
=> 441 – 247.5 / 247.5 x 100 = 193.5 / 247.5 x 100
78% in 2005 to match the sales figure of company R in 2004.

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Note:

The male population in UP and Maharashtra is more than the average

6.

What is the total number of students who did not pass the exams in schools B and C together. If 1100 students wrote the exams in each of schools B and C?

A.    1205 Wrong Right

B.    1210 Wrong Right

C.    1130 Wrong Right

D.    1195 Wrong Right

E.    None of these Wrong Right

Answer : 1210

Explanation : Number of students who did not pass in School B
=> 1100 x 66 / 100 = 726
=> Number of students, who did not pass in school C
=> = 1100 x 44 / 100 = 484
=> 726 + 484 = 1210

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7.

If the ratio of the number of students who wrote the exams in schools A and F is 8:13, then what is the ratio of the number of students in A and F who did not pass?

A.    23:16 Wrong Right

B.    21:23 Wrong Right

C.    16:21 Wrong Right

D.    17:21 Wrong Right

E.    21:17 Wrong Right

Answer : 16:21

Explanation : ratio of the total number of students in A and F = 8/13.
=> Ratio of the number of students, who failed, in both the schools
=> = 8 x 52 / 13 x 42 = 16 : 21

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8.

If in school D, the number of students who appeared for the exams in 1999-2000 is 20% more than that in the previous year and the number of students who passed in 1999-2000 is also 20% more than that in the previous year, then what is the ratio of the number of students who failed in 1998-1999 to that in 1999-2000?

A.    5:6  Wrong Right

B.    5:7  Wrong Right

C.    7:6  Wrong Right

D.    4:3  Wrong Right

E.    3:5 Wrong Right

Answer : 5:6 

Explanation : let us assume that the total number of students in school D in
=> 1998 – 1999 = 100
=> In 1999-2000 it is 120
=> Now given, number of students who failed in 1999-2000
=> 70 x 120 / 100 = 84
=> Number of students who failed in 1998-2000
=> 100 x 84/120 = 70
=> Required ratio = 70/84 = 5:6

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9.

If 140 students failed in school D in 1999-2000, then how many students did appear for the exam in the school that year?

A.    170 Wrong Right

B.    180 Wrong Right

C.    160 Wrong Right

D.    220 Wrong Right

E.    None of these Wrong Right

Answer : None of these

Explanation : total number of students appeared in exam in School D
=> 140 x 100 / 70 = 200

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10.

If the number of students who appeared for the exam in schools A and E forms 20% and 25% respectively of the total students who appeared for the exams in the given six schools, then what is the approximate ratio of the students who failed in schools A and E?

A.    2:3 Wrong Right

B.    4:5 Wrong Right

C.    3:4 Wrong Right

D.    1:1 Wrong Right

E.    5:4 Wrong Right

Answer : 3:4

Explanation : Let us assume that the total number of students appeared for exams in the given six schools = 1000. Number of students who appeared for exams in school
=> A = 2000
=> That in school E = 2500
=> Number, of students who failed in school
=> A = 2000 x 52 / 100 = 1040
=> Number of students who failed in school
=> E = 2500 x 55 / 100 = 1375
Required ratio = 1040/1375 = 208/275 = ¾

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Note:

The following line graph gives the percentage of the number of candidates who qualified an examination out of the total number of candidates who appeared for the examination over a period of seven years from 2004 to 2010





11.

The difference between the percentages of candidates qualified to appear was maximum in which of the following pairs of years?

A.    2004 and 2009 Wrong Right

B.    2007 and 2008 Wrong Right

C.    2008 and 2009 Wrong Right

D.    2009 and 2010  Wrong Right

Answer : 2004 and 2009

Explanation : from the given line graph, it is clear that the difference between the
=> Percentage of candidates qualified to appeared was maximum for the years 2004 and 2009 as 2004 has the minimum percentage while 2009 has the maximum percentage.

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12.

In which pair of years was the number of candidates qualified the same?

A.    2005 and 2007 Wrong Right

B.    2005 and 2010 Wrong Right

C.    2008 and 2009 Wrong Right

D.    Data inadequate  Wrong Right

Answer : Data inadequate 

Explanation : we can’t determine the actual number of qualified candidates as we
=> Don’t know the number of appeared students

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13.

If the number of candidates qualified in 2008 was 21200, what was the number of candidates appeared in 2008?

A.    32000 Wrong Right

B.    28500 Wrong Right

C.    26500 Wrong Right

D.    25000 Wrong Right

Answer : 26500

Explanation : let number of candidates appeared in 2008 be x,
=> Then, 80% of x = 21200
=> x = 21200 x 100/80 = 26500

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14.

If the total number of candidates appeared in 2006 and 2007 together was 47400, then the total number of candidates qualified in these two years together was

A.    34700 Wrong Right

B.    32100 Wrong Right

C.    31500 Wrong Right

D.    Data inadequate Wrong Right

Answer : Data inadequate

Explanation : Data is inadequate to answer this question as we don’t
=> Know the number of candidates appeared in 2006 and in 2007, separately.

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15.

The total number of candidates qualified in 2009 and 2010 together was 33500 and the number of candidates appeared in 2009 and 26500. What was the number of candidates appeared in 2010?

A.    24500 Wrong Right

B.    22000 Wrong Right

C.    20500 Wrong Right

D.    19000 Wrong Right

Answer : 20500

Explanation : Number of candidates appeared in 2009 = 26500
=>Therefore, number of candidates qualified in 2009
=> 80% of 26500 = 21200
=> Number of candidates qualified in 2010
=> 33500 – 21200 = 12300
=> Now, let the number of candidates appeared in 2010 be x.
=> Then, 60% of x = 12300
x = 12300 / 60 x 100 = 20500

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