Welcome Guest | Sign in | Register
Percentage - Discussion Page For Q.243 | Aptitude Questions and Answers | Aptitude Free Online-Tests | LucentBlackBoard | LucentBlackBoard.com

Home > Arithmetic Aptitude > Percentage > Questions and Answers Discussion

Q: The population of a town decreases at the rate of 5% every year. If the population of the town 2 years from now would be 902500, then what is the population of the town at present?
A. 1000000 B. 995000
C. 814500 D. 947625

Answer and Explanation

Answer:1000000

Explanation:
Explanation:
Population after 2 years = Present Population ( 1 – r1/100) (1 – r2/100)
P(1 – 5/100) (1 – 5/100) = 902500
P = 1000000

Comment on this Question

Name:

Loading...




Partner Sites
LucentBlackBoard.com                  SoftLucent.com                  LucentJobs.com
All rights reserved © 2012-2015 SoftLucent.